How to reduce for loops in C++

Question

How can I reduce the following program to 2 for loops and 1 print statement:

for (int i = 1; i <= iter; i++)
    {
        for (int j= 1; j <= row; j++) 
        {
            printf("*");
            for (int k = 1; k <= col; k++)
            {
                printf("_");
            }
            printf("*
");
        }
        printf("


");
    }

Answer 1

You can merge any count of loops, using multiplication and rest from division (just the multiplication has not to overflow).

void f(int iter, int row, int col) {
  for (int i = 0; i < iter * row * col; i++) {
    printf("%s%s%s%s", 
           i % col == 0 ? "*" : "",
           "_",
           i % col == col - 1 ? "*
" : "",
           i % (row * col) == (row * col) - 1 ? "


" : "");
  }
}